here it is:
Which system of equations can be used to solve the following problem?

Each child ticket for a ride costs $2, while each adult ticket costs $6. If the ride collected a total of $148, and 38 tickets were sold, how many of each type of ticket were sold? Let c be the number of child tickets and a be the number of adult tickets.

Question

here it is:
Which system of equations can be used to solve the following problem? 

Each child ticket for a ride costs $2, while each adult ticket costs $6. If the ride collected a total of $148, and 38 tickets were sold, how many of each type of ticket were sold? Let c be the number of child tickets and a be the number of adult tickets.

anonymous · Answer

@Catlover5925

anonymous · Answer

A. 2c+6a=148    a+c=38

B. 2a+6c=38       a+c=148

C. 6c+2a=148     c+a=38

D. 2c+6a=38       a+c=148

anonymous · Answer

those are my options

catlover5925 · Answer

first 
EQUATION --->2c + 6a = 148 C=child and A= adult

already knowing that you know the answer is A because child tickets were $2 and child was c, so it cant be B because it says 2a...and it cant be D because it put # of tickets at the end when it has to be money

FINAL ANSWER ----> A

anonymous · Answer

wow, you are amazing at this :D and a good explainer

catlover5925 · Answer

thanks, tag me anytime if u need help

anonymous · Answer

:)

anonymous · Answer

@cutegirl