Question

PLEASE I NEED HELP! JUST NEED ANSWERS ASAP!!!! MEDAL AND FAN!!!!!

Answer 1

A quadratic equation is shown below:

3x2 - 16x + 2 = 0

Part A: Describe the solution(s) to the equation by just determining the radicand. Show your work. (3 points)

Part B: Solve 9x2 + 3x - 2 = 0 by using an appropriate method. Show the steps of your work, and explain why you chose the method used. (4 points)

Part C: Solve 3x2 - 10x + 2 = 0 by using a method different from the one you used in Part B. Show the steps of your work. (3 points)

Answer 2

http://openstudy.com/study#/updates/5464f85ae4b04662b989982d

Answer 3

Mass tag can earn you a suspension. I'd suggest you delete the mass tags before you get a suspension or a warning from a moderator. Thank you. Just a little heads up:)

Answer 4

i cant help it, people wont help to i keep tagging to get help....

Answer 5

so*

Answer 6

Sure you can:) I'll help if you delete your comments:)

Answer 7

there all gone

Answer 8

@YanaSidlinskiy ?

Answer 9

Sorry, I'm kinda disturbed by a few people. I apologize.
Part A: Describe the solution(s) to the equation by just determining the radicand. Show your work
For part A, you are looking for the discriminant.
For parts B and C, you can use the quadratic formula.
\(a=3,\ b=-16,\ c=2\)

Answer 10

i am kind of slow so i was hoping to get some good answers.... i'm sorry ill try my best to understand this

Answer 11

Do know that I'm NOT going to give you a direct answer! It's against the CoC:)
Equation: \(ax^2+bx+c=0\)
\(discriminant\ (D)=b^2-4ac\)
to solve for the zeroes/solutions, you can use the quadratic formula
\(\Large x = \frac {-b \pm \sqrt {b^2 - 4ac}}{2a}\)

Answer 12

remember that "-tive" sign should be INSIDE the bracket, because you are squaring the value of b:
(−16)2−4(3)(2)=?

If the discriminant is positive, then the equation will have two solutions
if the discriminant is equal to zero, there is only one solution
if the discriminant is negative, then there is no solution.
I have to go now. Hopefully you'll understand. I have to go now. I'm sure someone will pick up and help you to the end.

Answer 13

@KamiBug @grov

Answer 14

i'm so lost right now