Question

PLZ HELP!!! WILL GIVE MEDAL

Answer 1

Part 1:
f you were solving a system of equations and you came to a statement like 1 = 3, what do you know about the solution(s) to this system?
Part 2:
Solve the following system and show all of your work.
x-2y =14
x+3y =9

Answer 2

this is what i got for part 1. Please check it for me and help me with part 2.

Part 1: The system 1=3 has no solution, so that means that the system has no solution.

Answer 3

Part 1 sounds correct, since \[1\neq3\]. For Part 2, I would either use elimination or substitution to solve for x and y. Do you know how to do that?

Answer 4

no i don't i searched google, but i didn't understand what they were saying

Answer 5

Ok, would you like me to show you how to solve the system of equations both ways or just one 'the easier method'?

Answer 6

probably the easier way

Answer 7

Okay, so we'll use elimination. So first you want to knock out 'eliminate' a variable to solve for the second variable.

Answer 8

\[\frac{ x-2y=14 }{ x+3y=9 } --> \frac{ -1(x-2y=14) }{ x+3y=9 }\] Multiply -1 to eliminate x and then add the new equation, turns the equation into \[\frac{ 2y=14 }{ 3y=9 } -- > 5y=-5 ---> y= -1\]

Answer 9

Use one of the original equations and plug in the value of y to solve for x. \[x-2y=14 --> x-2(-1) = 14--> x+2=14 --> x = 12\]

Answer 10

And always check, so just plug in the values of x and y into both equations to make sure they both equal the numbers they're supposed to