Question

Find the equation of the tangent line to the curve y

Answer 1

Find the equation of the tangent line to the curve y =4 secx-8cosx at the point(pi/3,4). The equation of this tangent line can be written in the form y=mx+b

Answer 2

okay so I have \[m = 4(2)(\sqrt{3})+8(\frac{ \sqrt{3} }{ 2 })\]

Answer 3

how do I find what 'b' is?

Answer 4

a tangent line is usually of the point slopr format, not the slope intercept format

Answer 5

given a point (a,f(a)) and a slope f'(a)

a point slope format is of the form:

y-f(a) = f'(a) (x-a)

Answer 6

this can be converted to slope intercept simply by expanding, and solving for y\

y = f'(a) x - a f'(a) + f(a)