HELP

2 variable:

the length of a red rectangle is 4 m more than its width. A blue rectangle, which is twice as wide and 2 m longer than the red one, has a perimeter of 42 m. Find the dimensions of both rectangles

Question

HELP

2 variable:

the length of a red rectangle is 4 m more than its width.  A blue rectangle, which is twice as wide and 2 m longer than the red one, has a perimeter of 42 m. Find the dimensions of both rectangles

anonymous · Answer

@jim_thompson5910  hi again. um i need help D:

jim_thompson5910 · Answer

"the length of a red rectangle is 4 m more than its width"

L = W+4

jim_thompson5910 · Answer

"A blue rectangle, which is twice as wide and 2 m longer than the red one"

blue rectangle has a width twice as wide

width of blue rectangle = 2W

and 2 m longer

length of blue rectangle = L + 2

jim_thompson5910 · Answer

blue rectangle has "perimeter of 42 m"


P = 2*(length + width)

P = 2*(L + 2 + 2W)

P = 2*(W+4 + 2 + 2W) ... plug in L = W+4

42 = 2*(W+4 + 2 + 2W)

solve for W