I'll medal for help!!!
I need to find a b and c but I always get messed up with the method :(
1.39= a(0)^2+b(0)+c
1.26= a(18)^2+b(18)+c
0= a(45)^2+b(45)+c

Question

I'll medal for help!!!
I need to find a b and c but I always get messed up with the method :(
1.39= a(0)^2+b(0)+c
1.26= a(18)^2+b(18)+c
0= a(45)^2+b(45)+c

anonymous · Answer

$$
1.39= a(0)^2+b(0)+c
$$This simplifies to: $$
1.39=c
$$

camzzzie · Answer

then plug c in?

anonymous · Answer

Yes

camzzzie · Answer

ok . How do you find just a or b when they are both in the equation?

anonymous · Answer

Isolate one of the variables.

camzzzie · Answer

0= a(45)^2+b(45)+ 1.39
-1.39-b(45)=a (45)^2

camzzzie · Answer

is that right?

anonymous · Answer

To isolate, you need to move the other variable to the other side of the equation.

anonymous · Answer

If you were to isolate a, for example, you would need to move over b, and then divide by the coefficient (number next to it) of a.