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Mathematics 8 Online
OpenStudy (anonymous):

calcu

OpenStudy (sidsiddhartha):

just break it up and put n=1,2,3,4

OpenStudy (sidsiddhartha):

\[\sum_{n=1}^{4}(n^2-2)=\sum_{n=1}^{4}n^2-\sum_{n=1}^{4}2\\=(1^2+2^2+3^2+4^2)-2\]

OpenStudy (sidsiddhartha):

got it?

OpenStudy (sidsiddhartha):

sigma means summation

OpenStudy (sidsiddhartha):

http://www.mathcentre.ac.uk/resources/uploaded/mc-ty-sigma-2009-1.pdf chech this out ,basics are all here

OpenStudy (sidsiddhartha):

take a example lets say u have to evaluate\[\sum_{n=1}^{5}n\\so \it~will~be~simply\\(1+2+3+4+5)\]

OpenStudy (sidsiddhartha):

take another example--\[\sum_{n=2}^{5}4n^2\\in~this~case~first~take~the~constant~out \\4 \sum_{n=2}^{5}n^2=4[2^2+3^2+4^2+5^2]\] like this :)

OpenStudy (sidsiddhartha):

now just simplify it

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