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calcu
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just break it up and put n=1,2,3,4
\[\sum_{n=1}^{4}(n^2-2)=\sum_{n=1}^{4}n^2-\sum_{n=1}^{4}2\\=(1^2+2^2+3^2+4^2)-2\]
got it?
sigma means summation
http://www.mathcentre.ac.uk/resources/uploaded/mc-ty-sigma-2009-1.pdf chech this out ,basics are all here
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take a example lets say u have to evaluate\[\sum_{n=1}^{5}n\\so \it~will~be~simply\\(1+2+3+4+5)\]
take another example--\[\sum_{n=2}^{5}4n^2\\in~this~case~first~take~the~constant~out \\4 \sum_{n=2}^{5}n^2=4[2^2+3^2+4^2+5^2]\] like this :)
now just simplify it
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