Question

A bit confused.
A landscaper plans to dig a rectangular garden whose length is to be 5 feet more than the width. If the landscaper has 42 feet of fencing to enclose the garden, what should be the dimensions of the garden?
I know I have to make 2 equations but not sure where to start ):

Answer 1

length = width + 5
perimeter = 2(length + width )

Answer 2

Okay thanks! Where do I go from now though...?

Answer 3

@sangya21

Answer 4

put length = width + 5 in second equation

Answer 5

Now
Perimeter = 2(width +(width+5) )
Perimeter is given so solve for width

Answer 6

It comes out being P=w+5?

Answer 7

P = 2(w+w+5)
P= 2(2w+5)

Answer 8

Okay so P=4w+5

Answer 9

And P=42 right?

Answer 10

I got the W should be 9.25

Answer 11

P= 2*2w +2*5 (distributive roperty)
P = 42
42 = 4w +10
42-10= 4w
so w= ??

Answer 12

Oops I messed up one sec

Answer 13

8?

Answer 14

So it's a 13x8 in diminsions?

Answer 15

Correct. :)

Answer 16

Awesome thanks so much!(:

Answer 17

anytime:)

Answer 18

Could you help me with one more?

Answer 19

Sure. :)