Will fan and medal! Solve right triangle ABC: C= 90*, A= 15*, and side b= 17.6. I found that angle B= 75* but how do I use tangent and cosine to find the sides of the triangle?
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sin B = opposite side/ hypotenuse sin 75 = 17.6 / h h * sin 75 = 17.6 h = 17.6 / sin 75 now grab ur calculator and work it out
Note I could have let hypotenuse = c you can find the length of the other side a by using tan 15 = a / 17.6
i got 18.220860…. is that right?
the was just an three dots.
18.22 is ok - correct to 2 decimal places
I think i was supposed to use tangent..the answer wouldn't have came out the same if i would have used tangent, right?
or was that for side c??
to find the hypotenuse you use sine or cosine
that was for side c
oh okay! that makes sense.
c = hypotenuse
gottcha
i used h by really it was better to use c (opposite angle C)
did you want to use the cosine to find c not the sine?
no, that's fine. I just forgot i could use sine as well for hypotenuse. what about side a? How would I find that?
to find side a you can use the tangent tan A = opposite / adjacent tan 15 = a / 17.6 a = 17.6 * tan 15
do you know SOH-CAH-TOA - helps you remember what each trig ratio means
Oh yeah, now i feel silly for not seeing that one! hahaha
Yes! Thank you so much for your help!
yw
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