Write the equation of the line that is parallel to the line 4x - 3y = -12 and passes through the point (-3, 4).??????????????

Question

anonymous · Answer

First, you need to get 4x-3y=-12 into slope-intercept form, which is y=mx+b. Can you do this?

ahsome · Answer

@pookie0799 , I am kinda busy so I cannot go step by step. I will later. Till then, what you need to do is find the $m$ value of that equation, which is the slope

Simply turn the equation into $y=mx+b$ and it should be easy from there

Then input that value, as well as the point onto this formula, which will give you your equation.
$y-y_1=m(x-x_1)$

anonymous · Answer

I know i got y=4x-8 ......but now what?

ahsome · Answer

Your $m$ is 4. Since your equation is in the form $y=mx+b$, your $m$ value is $4$

ahsome · Answer

Now, sub that value, as well as your point, into $y-y_1=m(x-x_1)$

anonymous · Answer

or you could sub (x,y) points into y=mx+b to solve for b..

ahsome · Answer

You could. But if you sub the value into the equation, then expand the bracketss, it will also give you the $b$ value