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Given tanB = 15/9 find angle B in degrees. Round your answer to the nearest hundredth. Explain/ show work pleasee
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Are you allowed to use a calculator?
yeah
If so, then note that \(\tan B = \dfrac{15}{9} \implies \tan^{-1}(\tan B)=\tan^{-1}\left(\dfrac{15}{9}\right) \implies B = \tan^{-1}\left(\dfrac{15}{9}\right)\). Most calculators should have the capability to compute this value. What kind of calculator are you using?
google lol
lol, that's fine. Just type in "inverse tangent of (15/9) in degrees" into google and it will give you an approximate value.
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59.036243?
Yes, so what would that be to the nearest hundredth?
59.04 thank you(:
You're welcome! :)
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