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Mathematics 21 Online
OpenStudy (anonymous):

....

OpenStudy (anonymous):

@kropot72

OpenStudy (perl):

probability ( diet sprite & water & water) = 4/40 * 10/39 * 9/38

OpenStudy (anonymous):

thanks, now I understand

OpenStudy (kropot72):

There are 40 drinks to choose from, and 4 diet sprites. So the probability of choosing a diet sprite first is 4/40. If a diet sprite is selected first, the probability of choosing a water next is 10/39, and the probability of then choosing another water is 9/38. You just need to multiply theses 3 values of probability together to find the required probability.

OpenStudy (kropot72):

these*

OpenStudy (anonymous):

thanks, kropot, you deserve this medal for your detailed explanations, thanks once again buddy

OpenStudy (anonymous):

Also I have a question, what was going to change if It said in any order other than in that order

OpenStudy (kropot72):

If the 1diet sprite and 2 waters can be in any order, the probability is given by: \[\large P(1\ diet\ sprite,\ 2\ waters)=\frac{4C1\times10C2}{40C3}\]

OpenStudy (anonymous):

oh, alright, thanks pal

OpenStudy (anonymous):

I just remembered that in combination order doesn't matter

OpenStudy (anonymous):

:D

OpenStudy (kropot72):

Cool! You're welcome :)

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