Question

What is the quadratic function that is created with roots at 2 and 4 and a vertex at (3, 1)? please show work

Answer 1

your quadratic equation is

y = a ( x - 2)( x - 4)

and you are given vertex , you can plug this in to solve for 'a'

Answer 2

1 = a ( 3 -2 ) ( 3 - 4)

Answer 3

okay the roots are given so the quadratic equation can be written as y=a(x-2)(x-4)
y=a(x^2-4x-2x+8)=a(x^2-6x+8)
now we have to find value of constant a
vertex=(3,1)
I pu x=3 and y=1 in the above equations and get the value of a
so I got 1=a(3^2-6 x 3 +8)
a=-1
so the quadratic equation is y=-(x^2-6x+8)
is this correct?^^

Answer 4

yes i got a = -1 as well

Answer 5

so y=-(x^2-6x+8) is my final answer, correct?

Answer 6

you should distribute the negative sign, might as well

Answer 7

can you send me the final answer after distributing?

Answer 8

y = -x^2 + 6x - 8

Answer 9

thank u:)