What is the equation of the line that passes through the points (-1, 3) and (1, 11)? 4x - y = 1 4x + y = 1 x - 4y = -13 4x - y = -7
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pokay listne
there are 2 points
\(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ &({\color{red}{ -1}}\quad ,&{\color{blue}{ 3}})\quad &({\color{red}{ 1}}\quad ,&{\color{blue}{ 11}}) \end{array} \\\quad \\ slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}} \\ \quad \\ y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values and move "x" and "y" to left side}\\ \qquad \uparrow\\ \textit{point-slope form}\)
baicall 1 line passes thru 2 points
ther is 1 slope and 1 yincetper that passes throug h2 ponts
Yeah I'm liatening.. Sorry I was busy :)
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@dan815
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