Help Me Please!!!!! F is the midpoint of AB and E is the midpoint of AC If FE=x+5 and BC=3x+2, what is FE? a.)10 b.)11 c.)12 d.)13
|dw:1416091496253:dw|
Please Help
:(
@jdoe0001 do you think you'd be able to help me??
it still hard to do, and i looked at that and i don't understand that.... :(
I just don't understand it at all, and I have looked at alot of examples but can never get it sadly :(
hmm well using the side-splitter theorem hmm lemme check
notice that the midsegment in that link DE is 1/2 of the longer AB
yes
|dw:1416092940110:dw| and you have those values thus we konw that FE = x+5 and that BC = 3x+2 thus \(\bf FE=x+5\qquad BC=3x+2\qquad FE=\cfrac{1}{2}BC\to \cfrac{BC}{2}\quad thus \\ \quad \\ x+5=\cfrac{3x+2}{2}\) solve for "x"
shoot okay so you would end up with x=2 am i right??
i don't think i did that correct....
well.. is not 2
okay so i did do that wrong..
so what is x???
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