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Physics 13 Online
OpenStudy (anonymous):

You are initially at rest at one end of a 3.00m platform (also initially at rest) that floats frictionlessly on a surface of slick oil. If you walk from one end of the platform to another with a constant velocity of 2.00m/s from one end of the platform to the other, what is the kinetic energy of the system just before you come to rest at the opposite end? ( you are 50kg, and the platform is 100kg)

OpenStudy (anonymous):

@PaxPolaris do you know how to do this?

OpenStudy (anonymous):

@kropot72

OpenStudy (anonymous):

@iGreen

OpenStudy (anonymous):

@arabpride

OpenStudy (anonymous):

@Compassionate

OpenStudy (anonymous):

@Jhannybean

OpenStudy (paxpolaris):

is it 0?

OpenStudy (paxpolaris):

if the system is you and the plank .... which is on a frictionless surface.... the center of mass of the system should not move while you walk from one end to the other. so i think KE of the system should be 0

OpenStudy (anonymous):

the total momentum would be 0 i think since the system is initally at rest

OpenStudy (anonymous):

the center of mass doesnt move?

OpenStudy (anonymous):

then how would you get to the other side you would be in the same place right

OpenStudy (paxpolaris):

the center of mass of you plus the plank.... my own clumsy ways of saying net momentum =0 ... you alone would have kinetic energy .... the plank alone shows KE ... but taken together as a system 0KE

OpenStudy (paxpolaris):

that's my opinion anyhow...

OpenStudy (anonymous):

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