Question

What is the equation of the line that passes through the points (-1, 3) and (1, 11)?

4x - y = 1
4x + y = 1
x - 4y = -13
4x - y = -7

Answer 1

Find slope
m = (y2-y1)/(x2-x1)
(x1,y1), (x2,y2) are given points
then use point slope formula
(y-y1)= m(x-x1)

Answer 2

@kaylamarie081 Please you have to substitute your coordiates in all of your equation, which you have wrote. When you get an identity, you have found the right equation

Answer 3

@kaylamarie081 please, you have to substitute both your points in each of your equation

Answer 4

sangya21 is right, but then you might have to convert your answer to the format the answer choices are in. Do you need help with that?

Answer 5

Yeah I really sick at math and no clue what I'm doing

Answer 6

Suck*

Answer 7

(x1,y1) = (-1, 3)
(x2,y2) = (1,11)
m = (y2-y1)/(x2-x1)
m = (11-3)/(1-(-1))
m = 8/2 = 4

then use point slope formula
(y-y1)= m(x-x1)
(y-3)= 4(x-(-1))
y - 3 = 4x +4
y = 4x +7

Answer 8

Is my answer B?

Answer 9

@sangya21

Answer 10

Its D
4x - y = -7
4x+7 = y