Question

Solve x^2-14x+58=0

Answer 1

Do you know about Quadratic Formula?

Answer 2

For equation like : \(ax^2 + bx + c = 0\)

\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]

Answer 3

In your equation : \(a=1\), \(b=-14\) and \(c = 58\)

Just plug in the values and find the value(s) of \(x\)..

Answer 4

I hope you are not sleeping right now. :P

Answer 5

x^2-14x+58=0
This implies (x^2-14x+49)+9=0
This implies (x-7)^2=-9
This implies x=7+/-3i

Answer 6

@HugoHuynh

Answer 7

option D is correct

Answer 8

@waterineyes see my solution.:)

Answer 9

Completing the square method is also good.. :)

Answer 10

Good use of brain.. :) @Princer_Jones :)

Answer 11

I would work with completing the square over quadratic formula any day.... even though one leads to the other <.< lol

Answer 12

Quadratic Formula is also derived by Completion of Square Method only.. :P