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Given 3 is one of the roots of the quadratic equation x^2-7x+k=0.Find the value of k.
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@UnkleRhaukus
roots means the value that make the equation =0
so since you have one root just put it instead of x the solve for k
(3)^2-7(3)+k=0
got it. answer will be k=12
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since 3 is a root then when x = 3 y = 0
yes
thnx @AJ01 @UnkleRhaukus @triciaal
as shown by @AJ01
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i think you made a switch the constant is ac the sum is b
ax^2+bx+c =0 the sum of the roots is -b/a the product of the roots is c/a x^2-7x+k=0 if the roots are 3 and m 3 + m = -(-7)/1 = 7 m = 4 the product of the roots is 3 * 4 = k / 1
tq @UnkleRhaukus
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