What is the equation of the graph below?
https://vcsohio.brainhoney.com/Resource/22138800,AB4,0,B,4/Assets/71871_53b5a642/5_14g_01.gif
y = -2(x - 3)2 + 1
y = -2(x + 3)2 + 1
y = 2(x - 3)2 + 1
y = 2(x + 3)2 + 1
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OpenStudy (anonymous):
@Directrix @sidsiddhartha
OpenStudy (sidsiddhartha):
firstly from the graph we can say that it is 3 unit from x axis and 1 from y axis .ok?
OpenStudy (anonymous):
so (3,1) right?
OpenStudy (sidsiddhartha):
yes so my first step will be
\[y=(x-3)^2+1\]
OpenStudy (anonymous):
what's the equation for it?
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OpenStudy (sidsiddhartha):
if the vertex is (h,k) then
\[y=(x-h)^2+k\\here\\h=3,k=1\]
ok?
OpenStudy (anonymous):
ok, I get that part, so what's next.
OpenStudy (sidsiddhartha):
now tell me that the graph opens downward or upward?
OpenStudy (anonymous):
downward, so it is negative right?
OpenStudy (sidsiddhartha):
yup good :)
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OpenStudy (sidsiddhartha):
so
\[y=-2(x-3)^2+1\]
OpenStudy (anonymous):
how did you get the 2?
OpenStudy (anonymous):
@sidsiddhartha ?
OpenStudy (sidsiddhartha):
uhh its lagging
OpenStudy (sidsiddhartha):
there shount be a 2
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OpenStudy (anonymous):
thanks!
OpenStudy (sidsiddhartha):
y = -(x - 3)^2 + 1
should be this
OpenStudy (anonymous):
I have another one I need help with. I'll post it and tag you