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OpenStudy (anonymous):
|dw:1416253840042:dw|
OpenStudy (anonymous):
@mathgeek27 @mathaddict4471 @mark1
myininaya (myininaya):
this is a fraction
what can you not have on the bottom of fractions?
OpenStudy (anonymous):
the c
myininaya (myininaya):
i'm asking what can you not divide by?
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myininaya (myininaya):
you can divide by 3 because 5/3 or 6/3 or 11/3 or -11/3 is a number
you can divide by -1 because 5/-1 or so on is a number
but you cannot divide by ?
OpenStudy (anonymous):
0
myininaya (myininaya):
right
to find the restrictions on the domain you need to find when the bottom will equal 0
myininaya (myininaya):
when is c-2 equal to 0
OpenStudy (anonymous):
wouldnt you adda negative to it
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myininaya (myininaya):
You are trying to solve c-2=0 .
How do you get c by itself?
myininaya (myininaya):
-2+what=0?
OpenStudy (anonymous):
add 2
myininaya (myininaya):
yes add 2 on both sides
myininaya (myininaya):
c-2=0
+2 +2
===========
c=2
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myininaya (myininaya):
So this means c can be any real number except 2
OpenStudy (anonymous):
ok
myininaya (myininaya):
if your question also says to simplify the expression you can do that as well by factoring the top
but the domain you just found will remain for the simplified version
OpenStudy (anonymous):
so c-2 will stay the same?
myininaya (myininaya):
no the domain will stay the same
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OpenStudy (anonymous):
oh okay
myininaya (myininaya):
are you done with this question? or is there more to it then finding the domain?
OpenStudy (anonymous):
thats it
myininaya (myininaya):
do you understand how to find the domain for a fraction now?
OpenStudy (anonymous):
yes thank you
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myininaya (myininaya):
\[\text{ the domain for } \frac{c^2-11c+18}{c-2} \text{ is } \\ \text{ all real numbers except c=2}\]