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Mathematics 9 Online
OpenStudy (anonymous):

Find the domain restrictions

OpenStudy (anonymous):

|dw:1416253840042:dw|

OpenStudy (anonymous):

@mathgeek27 @mathaddict4471 @mark1

myininaya (myininaya):

this is a fraction what can you not have on the bottom of fractions?

OpenStudy (anonymous):

the c

myininaya (myininaya):

i'm asking what can you not divide by?

myininaya (myininaya):

you can divide by 3 because 5/3 or 6/3 or 11/3 or -11/3 is a number you can divide by -1 because 5/-1 or so on is a number but you cannot divide by ?

OpenStudy (anonymous):

0

myininaya (myininaya):

right to find the restrictions on the domain you need to find when the bottom will equal 0

myininaya (myininaya):

when is c-2 equal to 0

OpenStudy (anonymous):

wouldnt you adda negative to it

myininaya (myininaya):

You are trying to solve c-2=0 . How do you get c by itself?

myininaya (myininaya):

-2+what=0?

OpenStudy (anonymous):

add 2

myininaya (myininaya):

yes add 2 on both sides

myininaya (myininaya):

c-2=0 +2 +2 =========== c=2

myininaya (myininaya):

So this means c can be any real number except 2

OpenStudy (anonymous):

ok

myininaya (myininaya):

if your question also says to simplify the expression you can do that as well by factoring the top but the domain you just found will remain for the simplified version

OpenStudy (anonymous):

so c-2 will stay the same?

myininaya (myininaya):

no the domain will stay the same

OpenStudy (anonymous):

oh okay

myininaya (myininaya):

are you done with this question? or is there more to it then finding the domain?

OpenStudy (anonymous):

thats it

myininaya (myininaya):

do you understand how to find the domain for a fraction now?

OpenStudy (anonymous):

yes thank you

myininaya (myininaya):

\[\text{ the domain for } \frac{c^2-11c+18}{c-2} \text{ is } \\ \text{ all real numbers except c=2}\]

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