Question

Will award a medal,
(dy/dx)+(y/3)=0 find the equation where when y=10 x=0. I had this problem for a calc II quiz today and got y=10e^(-x^2/6)

Answer 1

looks like a seperation of variables question
\[\frac{dy}{dx}=\frac{-y}{3} \\ \frac{dy}{y}=\frac{-1}{3} dx\]
integrate both sides

Answer 2

yea so you get ln|y|=-x^2/6+c

Answer 3

not exactly

Answer 4

\[\ln|y|=\frac{-1}{3}x+C\]

Answer 5

you didn't have an x next to -1/3

Answer 6

you know before integrating

Answer 7

bummer hopefully i get some partial credit

Answer 8

if you had \[\frac{dy}{y}=\frac{-1}{3}x dx \text{ then you would have } \ln|y|=\frac{-1}{3} \frac{x^2}{2} +C\]
which is what you got

Answer 9

it is possible you will get possible credit

Answer 10

partial*

Answer 11

you did integrate the other side correctly :)

Answer 12

hahaha