What is the formula for the following geometric sequence? 3, 12, 48, 192, ...
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OpenStudy (anonymous):
you always multiply a number by 4 so the nswer is 4x where x is greater than 0
OpenStudy (anonymous):
an = 4 · 3n - 1
an = 3 · (-4)n - 1
an = 3 · 4n - 1
an = (1/4) · 3n - 1
hmmmmmmmmmmmmmmmmmmmmmmm
OpenStudy (anonymous):
this looks strange let me think
OpenStudy (anonymous):
mmmm
OpenStudy (anonymous):
okay thank you
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OpenStudy (anonymous):
i not good at secuenses
OpenStudy (anonymous):
sorru
OpenStudy (blurbendy):
the formula for a geometric series is
an = a1*r^(n-1)
where a1 is the first term in the sequence, and r = common ratio
do you know how to find r?
OpenStudy (anonymous):
how
OpenStudy (blurbendy):
r is simply the ratio between the different numbers in the sequence.
3, 12, 48, 192....
You can find r by dividing farthest right number by the one before it
192/48 = 4
48/12 = 4
12/3 = 4
so r = 4
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OpenStudy (anonymous):
hmmmm. I understand somewhat. lol thank you though
OpenStudy (blurbendy):
all I did was divide the right term by the one to the left of it starting from 192
Each time, the answer was 4, so that is what r is.
OpenStudy (anonymous):
Got it!
OpenStudy (blurbendy):
cool.
OpenStudy (anonymous):
thanks!
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