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WILL GIVE A MEDAL What is the equation of a line that passes through point (1, -2) and has a slope of 1/3?
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y = mx+b is the general equation m is the slope b is the y-intercept
m = 1/3 is given
(1,-2) is the given point so x = 1 and y = -2
y = mx+b y = (1/3)*x+b -2 = (1/3)*(1)+b solve for b
But I got -7/3, but the answer choices are 3x - y - 7 = 0 x - 3y + 7 = 0 x - 3y - 7 = 0
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if use the more general form y=y1=m(x-x1) that would easier y-(-2)=1/3(x-1)
*(y-y1)=m(x-x1)
and then solve for y
okay just multbly the whole equation by 3
i hope that is clear now for you @z053sme
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