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Mathematics 20 Online
OpenStudy (anonymous):

Derive y=cos(sin(x^2))

OpenStudy (sidsiddhartha):

ok!! what have u done so far?

OpenStudy (anonymous):

would it be cos(cos(x^2)(2x) (-sin(sinx^2)) ?

OpenStudy (sidsiddhartha):

almost right check again u'll find your mistake :)

OpenStudy (sidsiddhartha):

\[y=\cos(sinx^2)\\y'=[-\sin(sinx^2)]*\cos(x^2).2x\] make sense? cahin rule!!

OpenStudy (sidsiddhartha):

*chain rule :)

OpenStudy (anonymous):

Ah, so derivative of outside times inside and then times derivative of inside

OpenStudy (sidsiddhartha):

yes thats the chain rule :)

OpenStudy (anonymous):

here's the re write http://puu.sh/cVwnh/a4c5c8f98e.png

OpenStudy (sidsiddhartha):

i dont see any mistake

OpenStudy (anonymous):

same here haha, unless there is another way to write this?

OpenStudy (sidsiddhartha):

yes try other ways

OpenStudy (sidsiddhartha):

any luck ??

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