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Derive y=cos(sin(x^2))
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ok!! what have u done so far?
would it be cos(cos(x^2)(2x) (-sin(sinx^2)) ?
almost right check again u'll find your mistake :)
\[y=\cos(sinx^2)\\y'=[-\sin(sinx^2)]*\cos(x^2).2x\] make sense? cahin rule!!
*chain rule :)
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Ah, so derivative of outside times inside and then times derivative of inside
yes thats the chain rule :)
i dont see any mistake
same here haha, unless there is another way to write this?
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yes try other ways
any luck ??
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