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Mathematics
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Implicit Differentiation of x^2-2xy+y^3=5
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you use the product rule to derive -2xy to get -2y - 2xy'
2x+2y-2xy'+3y^2y' ?
so it should be x^2-2xy+y^3=5 2x - 2y - 2xy' + 3y^2*y' = 0 solve for y'
-2y not +2y
tell me what you get for y'
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(2x+2y)/(2x+3y^2) ?
close, but incorrect
one moment
ok
(2(y-x))/(3y^2 -2x)
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that is the correct dy/dx expression
ah, thank you
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