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Mathematics 19 Online
OpenStudy (anonymous):

bit more help. thanks

OpenStudy (anonymous):

ganeshie8 (ganeshie8):

f(x,y) is the potential function, work done equals difference between `final and initial` values of potential

ganeshie8 (ganeshie8):

for c : P to T to Q final = Q initial = P work done = `value of f(x,y) at Q` - `value of f(x,y) at P`

OpenStudy (anonymous):

12-5 for part b. part a is shorter than.

ganeshie8 (ganeshie8):

i think u can simplify 12-5

OpenStudy (anonymous):

well, yeah.

OpenStudy (anonymous):

just in my notes putting that so i know where it came from. lol.

ganeshie8 (ganeshie8):

Okay :)

OpenStudy (anonymous):

so for part c is it still 12-5? start minus end? discounting the point in between? or does that matter?

ganeshie8 (ganeshie8):

the path doesnt matter for gradient fields

ganeshie8 (ganeshie8):

work done = final value - start value

ganeshie8 (ganeshie8):

so part b and c are same : 12-5

OpenStudy (anonymous):

ok, and the last one is 0 cause it starts and stops in the same place.

ganeshie8 (ganeshie8):

Yep!

OpenStudy (anonymous):

i thought part d would be 12-5 then (s-p), but it's not....

ganeshie8 (ganeshie8):

S --> P final = P start = S

ganeshie8 (ganeshie8):

it would be `5-12` for part d

OpenStudy (anonymous):

oh. backwards. lol. got it. very tired.

OpenStudy (anonymous):

thanks

ganeshie8 (ganeshie8):

its called fundamental theorem of line integrals, look it up in ur notes when free :)

OpenStudy (anonymous):

yeah, i have a notetaker for my ADHD so i can focus on paying attention and she hasn't posted yet.

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