bit more help. thanks
f(x,y) is the potential function, work done equals difference between `final and initial` values of potential
for c : P to T to Q final = Q initial = P work done = `value of f(x,y) at Q` - `value of f(x,y) at P`
12-5 for part b. part a is shorter than.
i think u can simplify 12-5
well, yeah.
just in my notes putting that so i know where it came from. lol.
Okay :)
so for part c is it still 12-5? start minus end? discounting the point in between? or does that matter?
the path doesnt matter for gradient fields
work done = final value - start value
so part b and c are same : 12-5
ok, and the last one is 0 cause it starts and stops in the same place.
Yep!
i thought part d would be 12-5 then (s-p), but it's not....
S --> P final = P start = S
it would be `5-12` for part d
oh. backwards. lol. got it. very tired.
thanks
its called fundamental theorem of line integrals, look it up in ur notes when free :)
yeah, i have a notetaker for my ADHD so i can focus on paying attention and she hasn't posted yet.
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