Question

Let y = 5 sqrt(x).
Find the change in y, ∆y when x= 4 and ∆x = 0.3

Answer 1

∆y = f(x+∆x) - f(x)
∆y = 5( x + ∆x)^(1/2) - 5x^(1/2)

This is as far as I got. Help please.

Answer 2

have you plugged in your given x and delta x?

Answer 3

the rest is plug in in and order of operations

Answer 4

\[\Delta y=5(4+0.3)^\frac{1}{2}-5(4)^\frac{1}{2}\]

Answer 5

@cjroyg are you still there?

Answer 6

Sorry my computer totally crashed.

Answer 7

But thank you for your assistance.

Answer 8

np