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OpenStudy (anonymous):
@AJ01
OpenStudy (anonymous):
@chosenmatt
OpenStudy (chosenmatt):
which number you think it is -2 or -1
OpenStudy (anonymous):
-1
OpenStudy (chosenmatt):
yup good job
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OpenStudy (anonymous):
what do i do now then @chosenmatt
OpenStudy (chosenmatt):
x=-1 what you just said so plug it in
OpenStudy (anonymous):
2*-1*2+5*-1+3
OpenStudy (anonymous):
@chosenmatt
OpenStudy (anonymous):
@mathmath333
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OpenStudy (mathmath333):
first u have to find the factors of
\(\Large ax^2+bx+c\)
\(\Large a \) and \(\Large c \) here
\(\Large 2x^2+5x+3\\
\)
\(\Large 2\times 3=6\)
therefore \(\Large 6\) has factors \(\Large 2\) and \(\Large 3\)
also \(\Large 2\) and \(\Large 3\) add to \(\Large 5\) which is the
\(\Large b\) term
hence u can write \(\Large b\) term which is \(\Large 5\) as
\(\Large 2+3\)
therefore
\(\Large 2x^2+5x+3\\
=\Large 2x^2+2x+3x+3\\
=\Large 2x(x+1)+3(x+1)\\
=\huge (x+1)(2x+3)\\\)