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Mathematics 20 Online
OpenStudy (anonymous):

what is the derivative of e^sinx?

OpenStudy (anonymous):

chain rule

OpenStudy (anonymous):

do you know chain rule?

OpenStudy (anonymous):

so is the answer cose^sinx + e^sinx??

OpenStudy (anonymous):

no

OpenStudy (anonymous):

first take the derivative of e^sinx the same as you would with e^x

OpenStudy (anonymous):

then multiply it by the derivative of sinx

OpenStudy (anonymous):

so the answer is (e^sinx)(cosx)

OpenStudy (anonymous):

thats it?

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

thank you!!

OpenStudy (anonymous):

quite simple really

OpenStudy (anonymous):

no problem :)

OpenStudy (anonymous):

how do you find the derivative of xe^-2x?

OpenStudy (anonymous):

do you know product rule?

OpenStudy (anonymous):

you gotta use a chain rule inside of product rule

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