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Mathematics 13 Online
OpenStudy (anonymous):

Geometry help? WILL MEDAL AND FAN!

OpenStudy (anonymous):

Number 6

OpenStudy (anonymous):

@StudyGurl14

OpenStudy (anonymous):

@nickmifsud1223

OpenStudy (anonymous):

@dan815 @TheSmartOne

OpenStudy (studygurl14):

special right traingle 45-45-90

OpenStudy (anonymous):

Okay. Do you know how to do it? Like, I never understand this stuff

OpenStudy (studygurl14):

If the leg is length 45, then the hypotenuse must be that, times the square root of 2.

OpenStudy (studygurl14):

So \(\large x=45\sqrt{2}\)

OpenStudy (anonymous):

Okay thank you :)

OpenStudy (studygurl14):

yep :)

OpenStudy (anonymous):

And y would equal?

OpenStudy (studygurl14):

There is no y...I'm talking about #5

OpenStudy (studygurl14):

oops, sorry i just realized you wanted #6

OpenStudy (anonymous):

lol okay its fine! Haha

OpenStudy (studygurl14):

Okay, so for #6...

OpenStudy (anonymous):

Yes

OpenStudy (studygurl14):

the length of the sides in red (see pic) , based on the info on 45-45-90 triangles, would be \(\large\frac{8}{\sqrt{2}}\)

OpenStudy (studygurl14):

OpenStudy (studygurl14):

OpenStudy (studygurl14):

Which means that \(\large x=\frac{8}{\sqrt{2}}\times2\) and \(\large y=\frac{8}{\sqrt{2}}\times\sqrt{3}\)

OpenStudy (anonymous):

Oh okay. thank you so much! I have to go, I'll be back in an hour or so

OpenStudy (studygurl14):

Simplify. You may also want to rationalize the denominator depending on what your teacher wants.

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