Mathematics
13 Online
OpenStudy (anonymous):
Geometry help? WILL MEDAL AND FAN!
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OpenStudy (anonymous):
Number 6
OpenStudy (anonymous):
@StudyGurl14
OpenStudy (anonymous):
@nickmifsud1223
OpenStudy (anonymous):
@dan815 @TheSmartOne
OpenStudy (studygurl14):
special right traingle 45-45-90
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OpenStudy (anonymous):
Okay. Do you know how to do it? Like, I never understand this stuff
OpenStudy (studygurl14):
If the leg is length 45, then the hypotenuse must be that, times the square root of 2.
OpenStudy (studygurl14):
So
\(\large x=45\sqrt{2}\)
OpenStudy (anonymous):
Okay thank you :)
OpenStudy (studygurl14):
yep :)
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OpenStudy (anonymous):
And y would equal?
OpenStudy (studygurl14):
There is no y...I'm talking about #5
OpenStudy (studygurl14):
oops, sorry i just realized you wanted #6
OpenStudy (anonymous):
lol okay its fine! Haha
OpenStudy (studygurl14):
Okay, so for #6...
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OpenStudy (anonymous):
Yes
OpenStudy (studygurl14):
the length of the sides in red (see pic) , based on the info on 45-45-90 triangles, would be
\(\large\frac{8}{\sqrt{2}}\)
OpenStudy (studygurl14):
OpenStudy (studygurl14):
OpenStudy (studygurl14):
Which means that
\(\large x=\frac{8}{\sqrt{2}}\times2\)
and
\(\large y=\frac{8}{\sqrt{2}}\times\sqrt{3}\)
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OpenStudy (anonymous):
Oh okay. thank you so much! I have to go, I'll be back in an hour or so
OpenStudy (studygurl14):
Simplify. You may also want to rationalize the denominator depending on what your teacher wants.