Question

factor -x^2+8x-2=0

Answer 1

(-x+(something))(x-(something smaller)

Answer 2

\[-x^2 +8x-2=0\] best method would be to complete the square. It's kind of like factoring I guess. \[(-x^2 +8x)-2=0\]factor out the negative value.\[-(x^2 -8x)-2=0\]complete the square.\[-(x^2 -8x +16-16) -2+16=0\] Because you factored out a negative value, you have to multiply the value you completed the square by, by a negative as well to keep it uniform.\[-(x-4)^2 +14 =0\]

Answer 3

thank you