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Mathematics 17 Online
OpenStudy (anonymous):

heeelp im horrible at math :(

OpenStudy (anonymous):

\[1-2\log_{7x} \] as a single logarithm

OpenStudy (michele_laino):

pleae rewrite your expression, I don't understand it!

OpenStudy (anonymous):

\[1-2\log _{7X}\]

OpenStudy (michele_laino):

is this? \[1-2\log _{7}x\]

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

common cait - you know this!

OpenStudy (anonymous):

it's so confusing to me now that its written differently:( @BPDlkeme234

OpenStudy (anonymous):

Go @Michele_Laino

OpenStudy (anonymous):

so it would be \[\log _{7}x ^{2}\] ?

OpenStudy (michele_laino):

Ok! I write: \[1-2\log _{7}x=\log _{7}7+2\log _{7}(\frac{ 1 }{ x })\]

OpenStudy (michele_laino):

and: \[=\log _{7}7+\log _{7}\frac{ 1 }{ x ^{2} }=\log _{7}(\frac{ 7 }{ x ^{2} })\]

OpenStudy (michele_laino):

@caitlynxoxo__98 here is your answer!

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