Question

Will give medal. Factor completely if possible. 16y^3 +24y^2 -16y

Answer 1

I got 8y(2y-x) (y+2) is this right

Answer 2

well 8y looks like a good common factor to start with

\[8y(2y^2 +3y - 2)\]

now all you need to do is factor the quadratic

Answer 3

8y(2y-1)(y+2)