Question

Write an equation of a line in slope intercept form that is perpendicular to the line 2x -3y = 12 and passes through the point (2, 6).

Having a lot of trouble with this.

Answer 1

is this on connections?

Answer 2

first, set your equation in slope interrupt form.... do you know how to ?

Answer 3

intercept *

Answer 4

No it is not @sWeetesttea

Answer 5

Do you mean y=mx+b?

Answer 6

@megzie

Answer 7

yes

Answer 8

Ok, so now what do I do?

Answer 9

what did you get?

Answer 10

I do not know how to turn this equation into slope intercept form

Answer 11

ok so right now you have: 2x-3y=12 and slope intercept form is: y=mx+b
This is what each letter means:
'm' is slope, this is a number you get with the 'x' symbol that is next to it.
'b' is the y-intercept, this is the number without a variable next to it.

Looking at the slope intercept form We can see that the 'y' is alone on the left. That's what we need to try and do. we have: 2x-3y=12, what do you do to get the '-3y' alone...?

Answer 12

Divide by -3?

Answer 13

@megzie

Answer 14

no,
This is our equation: 2x-3y=12

you have a '2x' on the same side as the 'y', what do you do with the '2x' so that the '-3y' can be alone?

Answer 15

So subtract 2x from both sides. -3y=12-2x

Answer 16

The answer is y=(-3/2)x + 9 :)

Answer 17

Thanks! But how did you get it?