The area of a rectangle is 48 square centimeters. The length of the rectangle is 8 centimeters longer than the width. Which equation models this situation?
A) w + 8 = 48
B) w(w + 8) = 48
C) 8w = 48
D) w + 8w = 48

Question

The area of a rectangle is 48 square centimeters. The length of the rectangle is 8 centimeters longer than the width. Which equation models this situation? 
A) w + 8 = 48
    B)   w(w + 8) = 48
     C)  8w = 48
     D)  w + 8w = 48

jhonyy9 · Answer

the length is 8 cm longer than the width so this mean l=w+8

anonymous · Answer

B.

campbell_st · Answer

its not B

anonymous · Answer

i still don't get it

anonymous · Answer

it is B.....
the formula to get an area of a rectangle is: length (L) x Width (W) = Area (A)
LxW=A 
We know that A=48 and we also know that the Length(L) is 8cm longer than the Width(W) which means: L= 8+W

Now we have two equations:
1st eqaution: 48=LxW
2nd equation: L=8+W

We know what the Length equals by looking at the second equation so use that and plug what L equals into the first equation.So now we would have: 48=(8+W)W

Which BY THE WAY is B. 

@campbell_st @NormaV

anonymous · Answer

jhonyy9, i don't understand what you mean

anonymous · Answer

are you ignoring my post.... i literally explained how you solve this whole equation....

anonymous · Answer

If you read what i wrote then you'll understand, I'm out of here. you're welcome by the way. @NormaV

anonymous · Answer

no i'm sorry my computer is lagging