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how to solve (x^2+3x+2)/x-3<= 0
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what i did was (x+2)(x+1)<=0 then i tested values on that line
and i got [-2,-1] is that correct?
sounds correct
keep in mind that, anything that's lower than -2, will also be lower than -1
not quite. After testing -2 and -1 using the number line test, you get x={(-infiniti, -1]}. That means x<= -1
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|dw:1416524332704:dw| thus
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