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(2/3)^(3x-2)=81/16
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\(\bf \left(\cfrac{2}{3}\right)^{3x-2}=\cfrac{81}{16} ?\)
x=1/3 :)
81/16 is equivalent to (9/4)^2. (2/3)^-2= 9/4 so multiply the exponents by -2. -6x + 4 = 2. X= 1/3.
Thank you and thank you for actually explaingin it, it took me a minute to understand, but that was great.
No problem! Do you understand fully? These types of problems are usually solved simply by getting the same base somehow, then setting the exponents equal to eachother
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right, i couldn't figure out how to get the same base, but Multiplying both sides by^-2 is how right?
kinda
Yes put (2/3)^-2 resulting with (9/4)
jessicacollin still confused?
no but i did get the correct answer which is -2/3
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