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Mathematics 19 Online
OpenStudy (anonymous):

suppose theta is an angle in the standard position whose terminal side is in quadrant 2 and Sec theta =-13/12. find the exact value of Tan theta. I need answer before 11 o'clock, I give free metals

OpenStudy (dumbcow):

easiest way it to use identity: \[\tan^2 = \sec^2 - 1\]

OpenStudy (dumbcow):

Note that since you are in quadrant 2, tangent will be negative

OpenStudy (anonymous):

so what's the answer? @dumbcow

OpenStudy (dumbcow):

you figure it out,i gave you the identity to use .... plug in value for sec to get tan

OpenStudy (anonymous):

I got tan=square root-13/12 is that correct? @dumbcow

OpenStudy (dumbcow):

nope ... cant take sqrt of neg number

OpenStudy (dumbcow):

|dw:1416542591005:dw|

OpenStudy (dumbcow):

i dont know how else to help you...plug in -13/12 for sec, then plug it into a calculator if you must

OpenStudy (dumbcow):

\[\tan = - \sqrt{(-\frac{13}{12})^2 - 1}\]

OpenStudy (anonymous):

thank you for your time and patients @dumbcow

OpenStudy (dumbcow):

yw

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