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Mathematics 15 Online
OpenStudy (anonymous):

The argument of √10cos(5π/7)+i√10sin(5π/6). I think it's -2.47/1.97

OpenStudy (anonymous):

Actually, wait. The -2.47/1.97 would be put into arctan, so it would be -0.897?

jimthompson5910 (jim_thompson5910):

r*(cos(theta) + i*sin(theta)) r = modulus theta = argument

OpenStudy (anonymous):

Oh. Really? It works differently than in (x + yi) form?

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