Question

Find the solution set of the equation.
2e^(3x-1) = 7

I understand the problem but the answer is :
{ 1/3 + 1/3ln(7/2) }

Answer 1

Take natural logs of both sides of the equation to begin:

2e^(3x-1) = 7

after dividing by 2.

e^(3x-1) = 7/2

ln(e^(3x-1) = ln(7/2)

What comes next?

Answer 2

Got it, thanks!!

Answer 3

Did you want to get the exact answer or an approximation? Just checking.

Answer 4

I just needed the solution set so { 1/3 + 1/3ln7/2 } works