Question

If R=(6√6+14)^2n+1 if f be the fractional part R then show that Rf=(20)^2n+1.

Answer 1

@ikram002p

Answer 2

brb

Answer 3

ok so the power is 2n+1 ?

Answer 4

\(R=(6\sqrt6+4)^{2n+1}\)

Answer 5

14

Answer 6

\[R=(6\sqrt[2]{6}+14)^{2n+1}\]