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Mathematics 4 Online
OpenStudy (anonymous):

Sketch an example of a relation with Domain {x | x ∈R} and Range {y | y ≥ -5, y∈R}. Is this sketch a function?

OpenStudy (anonymous):

Can someone help me please?

OpenStudy (anonymous):

x^2 - 5

OpenStudy (anonymous):

@sourwing can you roughly show me the sketch of it?

OpenStudy (anonymous):

|dw:1416612393908:dw|

OpenStudy (anonymous):

@sourwing We are being asked to explain why is it a function, can you list some its characteristics for me? that makes it a function?

OpenStudy (anonymous):

@sourwing

OpenStudy (zzr0ck3r):

a relation is a function if it is well defined and defined everywhere. well defined means that if x=y then f(x) = f(y) defined everywhere means that for all x in the domain , f(x) exists.

OpenStudy (zzr0ck3r):

one naive way to see well defined is if it passes the "vertical line test". Do you know about this?

OpenStudy (anonymous):

Nope, can you explain the vertical line test?

OpenStudy (zzr0ck3r):

if there is any spot that you can draw a line going straight up and down, and this lines passes through the graph more than once, then the graph does not represent a function

OpenStudy (zzr0ck3r):

Does this happen on the graph that @sourwing drew?

OpenStudy (zzr0ck3r):

imagine that he meant to draw it nice. not with all those crooked parts

OpenStudy (zzr0ck3r):

its the graph \(y=x^2-5\)

OpenStudy (anonymous):

I think I get the gist of you mean, the sketch is correct though right?

OpenStudy (zzr0ck3r):

well it should look smooth, but that is not so easy to draw with the tools on the site.

OpenStudy (anonymous):

alright, I think I get it, thank you so much :)

OpenStudy (zzr0ck3r):

It should look like this http://www.wolframalpha.com/input/?i=graph+y%3Dx%5E2-5

OpenStudy (anonymous):

yep, that's right :D Thanks again!

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