Question

PLEASE HELP!! I need an answer right away :(

Answer 1

Go ahead

Answer 2

This question has three parts. Here's the equation:
\[f(x)=2(x-4)^2+6\]

Answer 3

I have to find its Form.
Then convert it to vertex form.
And then convert it to the other equation form of a quadratic.

Answer 4

Ok the equation is in y-intercept form

Answer 5

y-intercept form? That would be... y=mx+b right?

Answer 6

right

Answer 7

Thank you! ^^

Answer 8

How should I convert it to vertex form though? :( Im not sure how to do it

Answer 9

y=a(x-h)^2+K is vertex form

Answer 10

Right >.< Here's what I was doing ...

Answer 11

I hope my writing is understandable enough >.<
But I got confused once I neared the end of it. Im not sure if im supposed to multiply 2 and x^2 to get 2x^2.

Answer 12

@JDizzle256

Answer 13

looks good

Answer 14

So this is the next step?
\[-6=2x^2-8x+16\]

Answer 15

ya

Answer 16

Do I subtract 16 from both sides?

Answer 17

yes

Answer 18

\[-22 = 2x^2 - 8x\]

Answer 19

ok thats good

Answer 20

ok now subtract 2x^2

Answer 21

From both sides?

Answer 22

mhm

Answer 23

\[-22 - 2x^2 = -8x \]
Like this?

Answer 24

yup then divide by -8 by all terms

Answer 25

why you have to divide by -8 ????

Answer 26

\[-22 - 2x^2/-8 = -8x/-8\]
Okay, -22 / -8 = 2.75 or 2 3/4
And Im not really sure how to divide 2x^2 by - 8...
Then -8x/-8 would cancel out...

Answer 27

becuase we are solving for x @Nnesha

Answer 28

Im confused >.<

Answer 29

ok first move -8x on left side then you can see which number you should divide by

Answer 30

quadratic equation is
Ax^2+Bx+C=0
you should divide by A not by B
make sense ???

Answer 31

Yes but I need to put the answer in vertex form.

Answer 32

y=a(x-h)^2+K
>.< But im not sure how im supposed to convert 22 - 2x^2 = -8x into this form.

Answer 33

@JDizzle256

Answer 34

Im so confused ;~;

Answer 35

@JDizzle256 @Nnesha

Answer 36

oh sorry I am just as confused :)

Answer 37

so what was your question ??

Answer 38

How do I convert this equation into vertex form? \[f(x)=2(x-4)^2+6\]

Answer 39

@Nnesha

Answer 40

that equation is already in vertex form

Answer 41

y = a(x - h)2+ k,
this is vertex form equation

Answer 42

I was thinking that it'd be like this.
\[f(x)=2(x-4)^2+6\]
And then on the right side of the equation, I'd expand the (x-4)^2 into...
\[2*(x-4)(x-4) +6\]
Resulting in
\[2* x^2 -4x -4x +16 + 6\]
And then simplifying it...
\[2x^2 - 8x + 22\]

Answer 43

So the equation should now look like this
\[0 = 2x^2 - 8x + 22\]
I believe Im supposed to subtract 22 from both sides.
\[-22=2x^2-8\]

Answer 44

-8x*

Answer 45

ohh that's mean you are changing to quadratic form

Answer 46

But that's not the form I want. I want Vertex Form :(((

Answer 47

And then after I get the vertex form, ill need the quadratic form afterwards.

Answer 48

may be you have to find the vertex ??

Answer 49

you are doing right changing equation to quadratic form