Chelsea is trying to find the equation of a quadratic that has a focus of (1, 3) and a directrix of y = –3. Describe to Chelsea your preferred method for deriving the equation. Make sure you use Chelsea's situation as a model to help her understand
you need to know what this looks like first plot the focus and directrix to see which way the parabola opens, then it is easy to find the equation lets draw the picture
|dw:1416628357689:dw|
now we know it faces up the \(x\) term is squared, and the vertex is halfway between \((1,3)\) and \(y=-3\) namely at \((1,0)\)
the equation is therefore \[4py=(x-1)^2\] and all you need is \(p\) which is the distance from the focus to the directrix, namely 3 so final answer is \[12y=(x-1)^2\] lets check it
yup it is right http://www.wolframalpha.com/input/?i=parabola+12y%3D%28x-1%29^2
Join our real-time social learning platform and learn together with your friends!