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Mathematics 20 Online
OpenStudy (anonymous):

Two number cubes are rolled. What are the odds that one cube will have at show at least 5 and the other cube will show a multiple of 3.

OpenStudy (anonymous):

number cubes? Are we talking about dice?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

I assume so, its how they presented the question.

OpenStudy (anonymous):

How many numbers on the die will be at least 5?

OpenStudy (anonymous):

that's the part I don't understand. The wording confuses me, I was hoping I could come here to get some clarification.

OpenStudy (anonymous):

Well, there are 6 sides, and 5 and 6 are at least 5.

OpenStudy (anonymous):

2/6?

OpenStudy (kropot72):

The sample space has 36 possible combinations of numbers. These can be set out in column form as follows: 6,6 5,6 4,6 3,6 2,6 1,6 6,5 5,5 4,5 3,5 2,5 1,5 6,4 5,4 4,4 3,4 2,4 1,4 6,3 5,3 4,3 3,3 2,3 1,3 6,2 5,2 4,2 3,2 2,2 1,2 6,1 5,1 4,1 3,1 2,1 1,1 You need to find how many of the outcomes show at least 5 on one cube and the other cube shows a multiple of 3. Let this number of outcomes be n, and let the event 'meets the specified outcome' be A. P(A) = n/36. Let the event 'does not meet the specified outcome' be B. P(B) = (36 - n)/36. The odds in favor of meeting the specified out come are: P(A) : P(B)

OpenStudy (anonymous):

So on it's own, 2 sides of 6 sides

OpenStudy (kropot72):

@Knamzy How many outcomes in the first column meet the specification?

OpenStudy (kropot72):

One cube has to have either a 5 or a 6, and the other cube has to have either a 6 or a 3.

OpenStudy (kropot72):

@Knamzy Are you there?

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