Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

in a room of 30 people, 22 like white, 23 like black, 24 like red, 25 like yellow. What's the minimum chance that I pick someone, and he happens to like all 4 colors

OpenStudy (anonymous):

no algebra allowed

OpenStudy (anonymous):

4

OpenStudy (swissgirl):

How did you figure that out?

OpenStudy (anonymous):

with my Yale brain

OpenStudy (anonymous):

First you add them up to get the number of color preferences:\[ 22+23+24+25 = 94 \]Now if all \(30\) people were to have \(3\) color preferences, then the total would be:\[ 30\times 3 = 90 \]

OpenStudy (anonymous):

The \(3\) color preferences is the minimum they can have without having \(4\).

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!