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\(\frac{x^{-3}+y ^{-3} }{ x ^{-1} +y ^{-1}}\) = ??? A. \(x ^{-2}+y ^{-3}\) B. \(x ^{-2}-y ^{-3}\) C. \(x ^{-2} - x ^{-1} y ^{-1}+y ^{-2}\) D. \(x ^{-2} + x ^{-1} y ^{-1}+y ^{-2}\) Why C not A????
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To make this problem easier, just let \(a = x^{-1}\) and \(b = y^{-1}\) So now we have \(\dfrac{a^3+b^3}{a+b}~\Longrightarrow~\dfrac{(a+b)(a^2-ab+b^2)}{a+b}\) I bet you know what to do from here.
oh...
umm, then a+b is cancelled...
Right, leave us \(a^2-ab+b^2\). Plug back in \(x^{-1}\) and \(y^{-1}\) And we have \(\boxed{x^{-2}-x^{-1}y^{-1}+y^{-2}}\)
oh i see. clear now. thank you so much
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