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pic above is the question
adding/subracting is easy in cartesian coordinates
change the given vectors to cartesian
\[\large \overrightarrow{q} = 3 \angle 307\] in cartesian it would be \[\large \overrightarrow{q} = (3\cos(307), ~3\sin(307)) \]
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similarly find the cartesian form for second vector
ok, let me try that, I have found something similar but it says wrong
i found the magnitude, how about the direction from standard position?
thx for helping
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is 83.02 right ?
i think you're right, u need to add 180 degrees to 83.02
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