Question

solve x^3-4x^2+5x+4=0

Answer 1

Since there are no rational factors. I guess I should use the Newton's Raphson Method to find the roots. Is that correct?

Answer 2

You could use that, OR use this equation to find it:

\[ay^3+(c-\frac{b^2}{3a})y+(d+\frac{2b^3}{27a^3}-\frac{bc}{3a})=0\]

Answer 3

That is the \(Cubic\) formula, similar to the quadratic formula, but for \(x^3\)

Answer 4

I didn't know there is a cubic formula. Thanks for the info

Answer 5

No problem @junyang96 :)

Answer 6

Actually, to my knowledge, that is actually the wrong equation @junyang96 ;). This is the right equation: